Arrange the following compounds in decreasing | vedclass

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(D) The heat of combustion is inversely proportional to the stability of the compound.Compound $(i)$ is $1,1,2,2$-tetramethylcyclopropane (a $3$-membe

Vedclass · Accepted Answer

$i > ii > iii$

Vedclass · Answer

(D) The heat of combustion is inversely proportional to the stability of the compound.Compound $(i)$ is $1,1,2,2$-tetramethylcyclopropane (a $3$-membered ring with high angle strain).Compound $(ii)$ is $1,2$-dimethylcyclopentane (a $5$-membered ring with moderate strain).Compound $(iii)$ is methylcyclohexane (a $6$-membered ring with minimal strain).Stability order: $(iii) > (ii) > (i)$.Therefore,the decreasing order of heat of combustion is $(i) > (ii) > (iii)$.

Arrange the following compounds in decreasing order of their heats of combustion:

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